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56x^2-81x+28=0
a = 56; b = -81; c = +28;
Δ = b2-4ac
Δ = -812-4·56·28
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-17}{2*56}=\frac{64}{112} =4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+17}{2*56}=\frac{98}{112} =7/8 $
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